There was a break in the rain today, and I walked around the Denny Triangle (in downtown Seattle) to check on the construction projects there.










A discussion on physics.stackexchange.com provides the answer. The principle of a lever in balance is that on the one side, distance times weight, is equal to distance times weight on the other side: d1.W1 = d2.W2. Earth weighs 6×10^24 kg. Let’s make the load arm length (opposite of Archimedes’s side) 1 m long, and assume he can push down with the force needed for 60 kg of weight. Say that gravity where he stands, is equal to that of Earth’s, and that Earth’s weight is concentrated where it meets the load point on the lever. Then the lever’s force arm length (on Archimedes’s side) would have to be 10^23 m. That is a distance of some 10 million light years. (About 4 times the distance between our own galaxy, the Milky Way, and Andromeda Galaxy, the nearest one to us).
If Archimedes pushed down on this intergalactical, perfectly rigid lever for 3 or 4 feet, Earth on the other end (10 million light years + 1 m away), would move by the diameter of an electron.















































































































